soal terlampir yh
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.
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Jan copas google
Jan ngasal
Rapi
Pakai cara
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easyy,,mmm bisa baca tulisan saia kan? ;_;
BA = Bsk dore _^_
--gdlk--
[tex] \tt1.) \: \: {2}^{3} \times 4![/tex]
[tex] \tt = (2 \times 2 \times 2) \times (4 \times 3 \times 2 \times 1 )[/tex]
[tex] \tt = (4 \times 2) \times (12 \times 2 \times 1)[/tex]
[tex] \tt = 8 \times 24[/tex]
[tex] \tt \red{ = 192}[/tex]
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[tex] \tt2.) \: \: 10 \times 2![/tex]
[tex] \tt = 10 \times (2 \times 1)[/tex]
[tex] \tt = 10 \times 2[/tex]
[tex] \tt = (10 + 10)[/tex]
[tex] \tt \red{ = 20}[/tex]
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[tex] \tt3.) \: \: \frac{4}{20} = \frac{4 \div 4}{20 \div 4} [/tex]
[tex] \tt \red{ = \frac{1}{5} }[/tex]
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[tex]{\colorbox{black}{\color{blue}{\boxed{\tt{✯zhadyy✯}}}}}[/tex]
Jawaban:
1). 2³ × 4!
= ( 2 × 2 × 2 ) × 4!
= ( 4 × 2 ) × 4!
= 8 × ( 4 × 3 × 2 × 1 )
= 8 × 24
= 192
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2). 10 × 2!
= 10 × ( 2 × 1 )
= 10 × 2
= 20
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[tex] \frac{4}{20} = \frac{4 \div 2}{20 \div 2} = \frac{2}{10} = \frac{2 \div 2}{10 \div 2} = \frac{1}{5} [/tex]
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